sairate<sairate@sina.cn>
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def is_zhi(n):
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if n==1:
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return 0
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if n==2:
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return 1
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is_zhi=1
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for i in range(2,n):
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if n%i==0:
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is_zhi=0
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return is_zhi
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def gede(n1,n2):
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if is_zhi(n1) and is_zhi(n2):
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print(n1, n2)
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return n1
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gede(n1-1,n2+1)
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#print(n1,n2,is_zhi(n1) , is_zhi(n2))
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n=int(input())
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gede(n-1,1)
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@ -0,0 +1,9 @@
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def han(start,end,temp,n):
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if n==1:
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return 0;
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else:
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han(start, temp, end, n - 1)
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print(n, start, "---->", end)
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han(temp, start, end, n - 1)
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han("A","B","C",5)
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def sieve_of_eratosthenes(n):
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primes = [True] * (n + 1) # 创建一个布尔列表,初始时所有元素设为True
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p = 2
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while p * p <= n:
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# 如果 primes[p] 未被标记为 False, 则是一个质数
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if primes[p]:
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# 更新所有 p 的倍数,从 p*p 开始标记为 False
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for i in range(p * p, n + 1, p):
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primes[i] = False
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p += 1
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# 收集所有质数
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prime_numbers = [p for p in range(2, n + 1) if primes[p]]
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return prime_numbers
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# 测试算法
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n = 50
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print(f"小于等于 {n} 的所有质数: {sieve_of_eratosthenes(n)}")
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