# 1 1 2 3 5
list=[]
for i in range(100000):
    list.append(0)
def feibo(n):
    if n==1 or n==2:
        return 1
    if list[n]!=0:
        return list[n]
    else:
        a=feibo(n-1)+feibo(n-2)
        list[n]=a
        return a
n=int(input())
b=feibo(n)
print(b%(10**9+7))