teacher_code_python/斐波那契数列.py

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2024-07-14 13:08:16 +08:00
# 1 1 2 3 5
list=[]
for i in range(100000):
list.append(0)
def feibo(n):
if n==1 or n==2:
return 1
if list[n]!=0:
return list[n]
else:
a=feibo(n-1)+feibo(n-2)
list[n]=a
return a
n=int(input())
b=feibo(n)
print(b%(10**9+7))